Given an integer x, return true if x is a palindrome, and false otherwise.

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Solution 1

C++

class Solution {
public:
    bool isPalindrome(int x) {
        if(x<0) return false;
        int t=x;
        long long y=0;
        while(t>0){
            y=y*10+t%10;
            t/=10;
        }
        return x==y;
    }
};

Solution 2

C++

class Solution {
public:
    bool isPalindrome(int x) {
        auto s=to_string(x);
        int i=0,j=s.size()-1;
        while(i<j && (s[i]==s[j])){
            i++;
            j--;
        }
        return i==j || i-j==1;
    }
};